First slide
Theory of equations
Question

If a, b, c are positive real numbers such that the equations ax2+bx+c=0 and bx2+cx+a=0 have a common root then 

Moderate
Solution

Let a be the common root of the two equations 

Then

and aα2+bα+c=0bα2+cα+a=0

Solving these two equations, we get

α2=αabc2a2=aba2acb2 and α=1acb2abc2acb2=bca2acb22abc2acb2=bca22aa3+b3+c33abc=0a3+b3+c33abc=0(a+b+c)a+bw+cw2a+bw+cw2=0 or a+bw2+cw=0 [a+b+c0]

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