If a, b,c are positive real numbers, then the roots of the equation ax2+bx+c=0

Roots of ax2+bc+c=0 are given byx=−b2a±b2−4ac2aWe have,a,b>0⇒−b/2a<0If b2−4ac<0 then roots are imaginary of which real part is negative.If b2−4ac>0 then roots are real and negative since b2−4ac