If a,b,c  are positive real numbers, then the roots of the equation ax2+bx+c=0 are

The given equation is ax2+bx+c=0 Roots of ax2+bx+c=0  are given by x=−b2a±b2−4ac2a Since a,b>0 , ∴ −b2a<0 if b2−4ac  is −ve , then roots are imaginary having real part negativeIf b2−4ac  is+ve , then roots real and negative.Hence both roots have negative real parts.