If a, b, c are positive then the minimum value of alogb−logc+blogc−loga+cloga−logb is
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a
3
b
1
c
9
d
16
answer is A.
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Detailed Solution
Since A.M. ≥ G.M.∴ alogb−logc+blogc−loga+cloga−logb3≥alogb−logc⋅blogc−loga⋅cloga−logb3 (1) Let x=alogb−logc⋅blogc−loga⋅cloga−logb⇒logx=(logb−logc)loga+(logc−loga)logb+(loga−logb)logc⇒ logx=0 ⇒x=1 ∴ From (1), alogb−logc+blogc−loga+cloga−logb≥3.