If a, b, c are real numbers in G.P. such that a and c are positive, then the roots of the equation ax2+bx+c=0
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a
are real and are in ratio b: ac
b
are real
c
are imaginary and are in ratio 1: ω, where ω is a complex cube root of unity
d
are imaginary and are in ratio - 1:ω
answer is C.
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Detailed Solution
We have, b2=acLet, a, β be the roots of the equation ax2+bx+c=0. Then,α, β=−b±b2−4ac2a= α, β=−ac±i3ac2a ∵b2=ac =α=−12+i32ca and, β=−12−i32ca=α=ωca and, β=ω2ca⇒α:β=1:ω