First slide
Monotonicity
Question

If a, b, c are real numbers, then the intervals in which f(x)  =  x+a2    ab     acab      x+b2  bcac       bc       x+c2  is strictly  decreasing

Moderate
Solution

f(x)=1abcax+a2ab2ac2a2bbx+b2bc2a2cb2ccx+c2=abcabcx+a2b2c2a2x+b2c2a2b2x+c2=x+a2+b2+c2b2c2x+a2+b2+c2x+b2c2x+a2+b2+c2b2x+c2=x+a2+b2+c21b2c21x+b2c21b2x+c2

=x2x+a2+b2+c2f(x)=3x2+2xa2+b2+c2f(x)<0x(3x+2)a2+b2+c2023a2+b2+c2x0

x(3x+2)023x0

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