If a,b,c are three distinct positive real numbers then the number of real roots of ax2+2b|x|−c=0 is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
0
b
4
c
2
d
None of these
answer is C.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
x=−2b±4b2+4ac2a a,b,c are positive. So, |x|=−b±b2+acx=±-b±b2+acx=-b+b2+ac, -b-b2+ac, b+b2+ac, b-b2+ac⇒x has two real values, neglecting x=−b−b2+ac, b-b2+ac as |x|≥0