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If A, B, C are three mutually exclusive and exhaustive events such that P(A)=3P(B)=4P(C) then P(A) =

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a

1219

b

719

c

517

d

1217

answer is A.

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Detailed Solution

PA+PB+PC=`1(1+13+14)P(A)=1⇒p(A)=1219

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