If a→,b→ and c→ are three mutually perpendicular vectors, then the vector which is equally inclined to these vectors is
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a
a→+b→+c→
b
a→|a→|+b→|b→|+c→|c→|
c
a→|a→|2+b→|b→|2+c→|c→|2
d
|a→|a→−|b→|b→+|c→|c→
answer is B.
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Detailed Solution
Let α→=a→|a→|+b→|b→|+c→|c→|Since a→,b→ and c→ are mutually perpendicular vectors, if α→makes angles θ,ϕ,ψ with a→,b→ and c→ respectively, thenα→⋅a→=a→⋅a→|a→|or |α→|⋅|a→|cosθ=|a→|or cosθ=1|α→|Similarly, cosϕ=1|α→|,cosψ=1|α→|