If a, b and c are three numbers (not necessarily different) chosen randomly and with  replacement from the set {1,2,3,4,5} , then the probability that (ab+c) is even, is

P(number  chosen is odd) = 3/5P(number chosen is even)=2/5 E: (ab+c) is even note that even E can occurs in two cases E1: all the three numbers a,b and ' c ' are odd PE1=353=27125E2: 'c' is even and at least one of a or b is even PE2=251−925=25⋅1625=32125P(E)=PE1 or E2=PE1+PE2=59125