If a,b,c are three unequal numbers such that a, b, c are in A.P and b−a, c−b, a are in G.P, then a : b : c is
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a
1 : 2 : 3
b
1 : 3 : 4
c
2 : 3 : 4
d
1 : 2 : 4
answer is A.
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Detailed Solution
Given that a, b, c are in A.P ⇒ 2b=a+c and b−a, c−b, a are in G.P.⇒ (c−b)2=(b−a)a ⇒ c2+b2−2bc=ab−a2 ⇒ c2+(a+c2)2−2(a+c2)c =a(a+c2)−a2 [using Eq. (i)] ⇒ c2+a2+c2+2ac4−ac−c2=a22+ac2−a2 ⇒ (c−a)2=2a(c−a) ⇒ c=3a (∵ c≠a) From Equation. (i) 2b=a+3a b=2a ∴ a : b : c=a : 2a : 3a =1 : 2 :3