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Q.

If  abc−2=bc+cb where a, b, c > 0 then family of lines ax+by+c=0 passes through the point

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a

(1,1)

b

(1,-2)

c

(-1,2)

d

(-1,1)

answer is D.

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Detailed Solution

a−2bc=b+c⇒(b+c)2−(a)2=0 or b+c−a=0 (∵b+c+a≠0)∴ax+by+c passes through the fixed point (-1, 1)
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If  abc−2=bc+cb where a, b, c > 0 then family of lines ax+by+c=0 passes through the point