If 9a2+25b2−c2+30ab=0 , then the set of lines ax+by+c=0 passes through the fixed point is
3,5
−3,−5
3,5,−3,−5
No fixed point
The given condition is 9a2+25b2−c2+30ab=0
This can be rewrite as
3a+5b2−c2=03a+5b−c3a+5b+c=0
It implies that
3a+5b−c=0, or 3a+5b+c=0
comparing the above equations with ax+by+c=0.
x=−3,y=−5 or x=3,y=5
Therefore, the fixed points are (−3,−5) or (3,5)