First slide
Harmonic Progression
Question

 If 1a+1a2b+1c+1c2b=0 and a,b,c are not in A.P then: 

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Solution

1a+1a2b+1c+1c2b=02(ab)a(a2b)+2(cb)c(c2b)=0aba(a2b)+cbc(c2b)=0 Now, we can verify the result that a,2b,c are in H.P 

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