If a,b,c,d and p are distinct non zero real numbers such that a2+b2+c2p2-2(ab+bc+cd)p+b2+c2+d2≤0 then a,b,c,d are in
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a
A.P
b
G.P
c
H.P
d
satisfy ab=cd
answer is B.
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Detailed Solution
a2+b2+c2p2−2(ab+bc+cd)p+b2+c2+d2≤0⇒a2p2−2abp+b2+b2p2−2bcp+c2+c2p2−2cdp+d2≤0 ⇒ab-p2+bp-c2+cp-d2≤0⇒ap−b=0,bp−c=0 and cp−d=0⇒ba=cb=dc⇒a,b,c and d are in GP Also ad =bc