If a,b,c,d∈R, then the equation x2+ax−3bx2−cx+bx2−dx+2b=0 has

The discriminants of the given equations are D1=a2+12b,D2=c2−4b and D3=d2−8b.∴ D1+D2+D3=a2+c2+d2≥0Hence, at least one of D1, D2,D3 is non-negative. Therefore, the equation has at least two real roots.