If a2+b2+c2=-2  and  f(x)=1+a2x1+b2x1+c2x1+a2x1+b2x1+c2x1+a2x1+b2x1+c2x then f(x) is a polynomial of degree

Applying , C1→C1+C2+C3 we get f(x)=11+b2x1+c2x11+b2x1+c2x11+b2x1+c2x                       [using a2+b2+c2=-2]Applying R2→R2-R1 and R3→R3-R1,we get f(x)=11+b2x1+c2x 01x0001-x =(1-x)2which is a polynomial of degree 2.