If a △ABC the mid points of the sides AB,BC,CA are respectively (l,0,0),(0,m,0) and (0,0,n) then
AB2+BC2+CA2l2+m2+n2=
2
4
8
16
We have
A+B=2l,0,0, B+C=0,2m,0 and C+A=0,0,2n ⇒A=l,-m,n, B=l,m,-n and C=-l,m,n ∴AB2+BC2+CA2l2+m2+n2=4m2+4n2+4l2+4n2+4l2+4m2l2+m2+n2=8