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Questions  

 If a ABC the mid points of the sides AB,BC,CA are respectively (l,0,0),(0,m,0) and (0,0,n) then

AB2+BC2+CA2l2+m2+n2=

 

a
2
b
4
c
8
d
16

detailed solution

Correct option is C

We have A+B=2l,0,0, B+C=0,2m,0 and C+A=0,0,2n ⇒A=l,-m,n, B=l,m,-n and C=-l,m,n ∴AB2+BC2+CA2l2+m2+n2=4m2+4n2+4l2+4n2+4l2+4m2l2+m2+n2=8

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