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Questions  

If A+B+C=π,nZ,then tannA+tannB+tannC is equal 

a
0
b
1
c
tan⁡nAtan⁡nBtan⁡nC
d
none of these

detailed solution

Correct option is C

We have , A+B+C=π⇒nA+nB+nC=nπ

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