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If A,B,C,P,Q,RR and Δ=cos(A+P)    cos(A+Q)    cos(A+R)cos(B+P)    cos(B+Q)    cos(B+R)cos(C+P)    cos(C+Q)    cos(C+R)

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a
Δ depends on P,Q,R
b
Δ depends on A,B,C
c
Δ depends on A,B,C,P,Q,R
d
none of these

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detailed solution

Correct option is D

WriteΔ=cos⁡Asin⁡A0cos⁡Bsin⁡B0cos⁡Csin⁡C0cos⁡P−sin⁡P0cos⁡Q−sin⁡Q0cos⁡R−sin⁡R0=0Alternate SolutionWrite Δ=cos⁡PΔ1−sin⁡PΔ2write Δ1=cos⁡A    cos⁡(A+Q)    cos⁡(A+R)cos⁡B    cos⁡(B+Q)    cos⁡(B+R)cos⁡C    cos⁡(C+Q)    cos⁡(C+R)and Δ2=sin⁡A    cos⁡(A+Q)    cos⁡(A+R)sin⁡B    cos⁡(B+Q)    cos⁡(B+R)sin⁡C    cos⁡(C+Q)    cos⁡(C+R)In Δ1,use C2→C2−cos⁡QC1C3→C3−cos⁡RC1Δ1=cos⁡A    sin⁡Asin⁡Q    sin⁡Asin⁡Rcos⁡B    sin⁡Bsin⁡Q    sin⁡Bsin⁡Rcos⁡C    sin⁡Csin⁡Q    sin⁡Csin⁡R=0                     ∵C2 and C3 are propotional Similarly, Δ2=0Thus ∆ = 0


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