First slide
Properties of triangles
Question

If ABC,8R2=a2+b2+c2, then the triangle ABC, is

Moderate
Solution

We have,

8R2=a2+b2+c28R2=4R2sin2A+sin2B+sin2Csin2A+sin2B+sin2C=21cos2A+1cos2B+sin2C=2cos2Asin2C+cos2B=0cos(A+C)cos(AC)+cos2B=0cosB{cos(AC)cosB}=0cosB{cos(AC)+cos(A+C)}=02cosAcosBcosC=0cosA=0 or, cosB=0 or, cosC=0A=π2 or, B=π2 or, C=π2

 ABC is a right angled triangle

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