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If $a + b + c \neq 0$ the system of equations $(b + c) (y + z) - a x = b - c,$ $(c + a) (z + x) - b y = c - a, (a + b) (x + y) - c z = a - b$ has

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b+cy+z−ax=b−c_______1a+bx+y−cz=a−b_______2c+az+x−by=c−a_______3From equations 1,2, and 3 we havex=c−ba+b+c, y=a−ca+b+c, z=b−aa+b+c

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If a+b+c≠0the system of equations b+cy+z−ax=b−c, c+az+x−by=c−a, a+bx+y−cz=a−b has

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If $a + b + c \neq 0$ the system of equations $(b + c) (y + z) - a x = b - c,$ $(c + a) (z + x) - b y = c - a, (a + b) (x + y) - c z = a - b$ has