If 4a→+5b→+9c→=0, then (a→×b→)×[(b→×c→)×(c→×a→)] is equal to
a vector perpendicular to the plane of a→,b→ and c→
a scalar quantity
0→
none of these
4a→+5b→+9c→=0⇒ Vectors a→,b→ and c→ are coplanar. ⇒ b→×c→ and c→×a→ are collinear ⇒ (b→×c→)×(c→×a→)=0→