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If , then a root of the equation is
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a
1
b
-1
c
a2+b2+c2
d
0
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Correct option is D
Applying C1→C1+C2+C3, we get Δ=a+b+c-xcba+b+c-xb-xaa+b+c-xac-x=-xcb-xb-xa-xac-x [∵a+b+c=0]∆clearly equals 0 when x = 0. It is unnecessary to evaluate the determinant further.Similar Questions
Let .Then equal to
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