First slide
Theory of equations
Question

If a+b+c=0, then the roots of the equation 4ax2+3bx+2x=0 are

Moderate
Solution

We have 4ax2+3bx+2x=0 Let roots are α and β

Let D=B2-4 AC=9b2-4(4a)(2c)=9b2-32ac

Given that, (a+b+c)=0b=-(a+c)

Putting this value, we get

=9(a+c)2-32ac=9(a-c)2+4ac.

Hence roots are real.

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