If a+b+c=0, then the roots of the equation 4ax2+3bx+2x=0 are

We have 4ax2+3bx+2x=0 Let roots are α and βLet D=B2-4 AC=9b2-4(4a)(2c)=9b2-32acGiven that, (a+b+c)=0⇒b=-(a+c)Putting this value, we get=9(a+c)2-32ac=9(a-c)2+4ac.Hence roots are real.