If a+b+c=0, then the roots of the equation 4ax2+3bx+2x=0 are
Equal
Imaginary
Real
None of these
We have 4ax2+3bx+2x=0 Let roots are α and β
Let D=B2-4 AC=9b2-4(4a)(2c)=9b2-32ac
Given that, (a+b+c)=0⇒b=-(a+c)
Putting this value, we get
=9(a+c)2-32ac=9(a-c)2+4ac.
Hence roots are real.