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If then system of equations , has
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a unique solution
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infinite number of solutions
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Correct option is A
We can write the above system of equations as (a+b+c)(y+z)−a(x+y+z)=b−c(a+b+c)(z+x)−b(x+y+z)=c−a,(a+b+c)(x+y)−c(x+y+z)=a−bAdding the above equations , we obtain 2(a+b+c)(x+y+z)−(a+b+c)(x+y+z)=0⇒(a+b+c)(x+y+z)=0⇒x+y+z=0⇒y+z=−x∴(b+c)(−x)−ax=b−c⇒x=c−ba+b+c. similarly ,y=a−ca+b+c,z=b−aa+b+cSimilar Questions
The number of solutions of
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