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Q.

If A+B+C=πthen the value of tanA+tanB+tanCtanA.tanB.tanC+cotAtanB+cotBtanC+cotCtanA

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a

1

b

2

c

3

d

4

answer is B.

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Detailed Solution

A+B+C=π⇒ tanA+tanB+tanC=tanAtanBtanC and cotAcotB+cotBcotC+cotCcotA=1⇒cotAtanB+cotBtanC+cotCtanA=1 ∴tanA+tanB+tanCtanAtanBtanC+cotAtanB+cotBtanC+cotCtanA=1+1=2
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