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Q.

If a,b∈Rand ax2 +bx +6=0,a≠0 does not have distinct real roots, the

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a

minimum possible value of 3a + b is -2

b

minimum possible value of 3a+ b is 2

c

minimum possible value of 6a+ b is -1

d

minimum possible value of 6a + b is 1

answer is A.

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Detailed Solution

Here, D ≤ 0and f(x)≥0,∀x∈R∴f(3)≥0⇒9a+3b+6≥0 or 3a+b≥−2Minimum value of 3a + b is - 2.and f(6) ≥036a +6b+6≥06a + b ≥ -1Minimum value of 6a + b is -1.
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