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Q.

If 3A+4BT=(7   −10   170        6     31)  and 2B−3AT=  (−1      184       −6−5    −7)  then B=

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a

(  1           3 −1         0−2     −4)

b

(1     31     02    4)

c

(1         3−1     02       4)

d

(1        − 31          02         4)

answer is C.

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Detailed Solution

(3A+4BT)T =3AT+4B=70-1061224   ------------(1)given 2B-3AT=-1184-6-5-7-----------(2)adding (1) and (2)6B=618-601224
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