If $$3A+4BT=(7$$ −$$10$$ $$170$$ $$6$$ $$31)$$ and $$2B$$−$$3AT=$$ $$($$−$$1$$ $$184$$ −$$6$$−$$5$$ −$$7)$$ then $$B=$$

Correct option is 3(1 3−1 02 4)

Questions

If $3 A + 4 B^{T} = (\begin{matrix} 7 - 10 17 \\ 0 6 31 \end{matrix})$ and $2 B - 3 A^{T} =$ $(\begin{matrix} - 1 18 \\ 4 - 6 \\ - 5 - 7 \end{matrix})$ then $B =$

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( 1 3 −1 0−2 −4)

(1 31 02 4)

(1 3−1 02 4)

(1 − 31 02 4)

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detailed solution

Correct option is C

(3A+4BT)T =3AT+4B=70-1061224 ------------(1)given 2B-3AT=-1184-6-5-7-----------(2)adding (1) and (2)6B=618-601224

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If 3A+4BT=(7 −10 170 6 31) and 2B−3AT= (−1 184 −6−5 −7) then B=

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If $3 A + 4 B^{T} = (\begin{matrix} 7 - 10 17 \\ 0 6 31 \end{matrix})$ and $2 B - 3 A^{T} =$ $(\begin{matrix} - 1 18 \\ 4 - 6 \\ - 5 - 7 \end{matrix})$ then $B =$