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If $a = 99^{50} + 100^{50}$ and $b = 101^{50}$ then

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a < b

a = b

a > b

a – b = 10049

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detailed solution

Correct option is A

10150−9950=(100+1)50−(100−1)50=2 50C1(100)49+50C3(100)47+…+50C49(100)\=10050+ a positive term.⇒b = a + (a positive term) ⇒a < b.

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If a=9950+10050 and b=10150 then

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If $a = 99^{50} + 100^{50}$ and $b = 101^{50}$ then