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If $A = 1000^{1000}$ and $B = (1001)^{999}$ then

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A>B

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Correct option is A

Since, 1+1nn<3 for ∀n∈NNow (1001)999(1000)1000=11001⋅100110001000 =110011+110001000<11001⋅3<1(1001)999<(1000)1000

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If A=10001000 and B=(1001)999 then

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If $A = 1000^{1000}$ and $B = (1001)^{999}$ then