First slide

Operations of matrix

Question

If $A = [\begin{array}{lll} 1 - 2 3 \end{array}], B = [\begin{array}{r} 2 \\ - 3 \\ - 1 \end{array}]$ , then AB is equal to

Easy

A

$[\begin{array}{r} 2 \\ - 3 \\ - 1 \end{array}]$
B

$[\begin{array}{r} 2 \\ 6 \\ - 3 \end{array}]$
C

$[\begin{array}{ll} 2 6 - 3 \end{array}]$
D

none of these

Solution

$A B = [\begin{array}{lll} 1 - 2 3 \end{array}] [\begin{array}{r} 2 \\ - 3 \\ - 1 \end{array}] = [\begin{array}{l} 2 + 6 - 3 \end{array}] = [5]$

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