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$If A = [\begin{array}{cc} 2 & 2 \\ - 3 & 2 \end{array}], B = [\begin{array}{cc} 0 & - 1 \\ 1 & 0 \end{array}], then {(B^{- 1} A^{- 1})}^{- 1}$

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2−223

3−222

11022−23

11032−22

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Correct option is A

B−1A−1−1=A−1−1B−1−1=AB=22−320−110=0+2−2+20+23+0=2−223

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2023 | www.infinitylearn.com

If A=22−32,B=0−110, then B−1A−1−1

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$If A = [\begin{array}{cc} 2 & 2 \\ - 3 & 2 \end{array}], B = [\begin{array}{cc} 0 & - 1 \\ 1 & 0 \end{array}], then {(B^{- 1} A^{- 1})}^{- 1}$