If A={1,2,3,4},B={3,4,5} then thenumber of elements in (A∪B)×(A∩B)×(AΔB) is

A∪B={1,2,3,4,5},n(A∪B)=5 A∩B={3,4},n(A∩B)=2AΔB=(A~B)∪(B~A)={1,2}∪{5} ={1,2,5}n(AΔB)=3 Hence n((A∪B)×(A∩B)×(AΔB)}=5×2×3=30