If a ≠ b, then the roots of the equation 2a2+b2x2+2(a+b)x+1=0 are
real and distinct
real and equal
imaginary
None of the above
The given equation is 2a2+b2x2+2(a+b)x+1=0Now, D=4(a+b)2−8a2+b2=−4a2+b2−2ab=−4(a−b)2<0 (∵a−b≠0)Hence, the roots of the given equation are imaginary.