If a ≠ b, then the roots of the equation 2a2+b2x2+2(a+b)x+1=0 are

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real and distinct

real and equal

imaginary

None of the above

answer is C.

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Detailed Solution

The given equation is 2a2+b2x2+2(a+b)x+1=0Now, D=4(a+b)2−8a2+b2=−4a2+b2−2ab=−4(a−b)2<0 (∵a−b≠0)Hence, the roots of the given equation are imaginary.

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