First slide
Theory of equations
Question

If a  b, then the roots of the equation 2a2+b2x2+2(a+b)x+1=0 are

Moderate
Solution

The given equation is 2a2+b2x2+2(a+b)x+1=0
Now,
 D=4(a+b)28a2+b2=4a2+b22ab=4(ab)2<0 (ab0)
Hence, the roots of the given equation are imaginary.

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