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Q.

If (21.4)a=(0.00214)b=100, then the value of 1a−1b is

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a

0

b

1

c

2

d

4

answer is C.

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Detailed Solution

(21.4)a=100⇒ alog⁡(21.4)=2∴ log⁡(21.4)=2/afrom (0.00214)b=100 we getor  b(log⁡0.00214)=2or  blog⁡21.4×10−4=2b=2log⁡21.4−4=22a−4=11a−2=a1−2a⇒1b=1−2aa⇒1a−1b=2
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If (21.4)a=(0.00214)b=100, then the value of 1a−1b is