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Q.

If A(−4,0,3) and B(14,2,−5) then which one of the following points lie on the bisector of the angle between OA→ and OB→ (O is the origin of reference)?

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a

(2,2, 4)

b

(2, 11, 5)

c

(-3, -3, -6)

d

(1,1, 2)

answer is A.

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Detailed Solution

OA→=−4i^+3k^;OB→=14i^+2j^−5k^a^=−4i^+3k^5;b^=14i^+2j^−5k^15r→=λ15[−12i^+9j^+14i^+2j^−5k^]=λ15[2i^+2j^+4k^] =2λ15[i^+j^+2k^]
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