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Questions  

If a,b,x,yR, ω1, is a cube root of unity and (a+bω)7=x+yω, then (b+aω)7equals

a
y+xω
b
-y-xω
c
x+yω
d
-x-yω

detailed solution

Correct option is A

Taking conjugate, we get a+bω27=x+yω2⇒aω3+bω27=xω3+yω2ω14(aω+b)7=ω2(xω+y)⇒ (aω+b)7=xω+y

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