If a,b,c are in A.P, the lines ax+by+c=0 pass through the fixed point
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a
(1,2)
b
(−1,2)
c
(1,−2)
d
(−1,−2)
answer is C.
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Detailed Solution
a,b,c are in A.P. 2b=a+c c=2b-a substituting in the line ax+by+c=0 ax+by+2b-a=0 a(x-1)+b(y+2)=0 is a family of straight lines which are concurrent The point of concurrence is x-1=0 ⇒x=1 y+2=0 ⇒y=-2