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Q.

If A,B,C,D are the slopes of the tangents to the curves y=6+x−x2 at (2,4), y=sinx at x=π4,y=tanx at x=π3 and y2=10x at (10,10) respectively then the ascending order is

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a

A, B, C, D

b

B, C, D, A

c

A, D, B, C

d

C, D, B, A

answer is C.

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Detailed Solution

y=6+x−x2 dydx=1−2x⇒slope=−3=A y=sinx dydx=cosx⇒slope=12=B y=tanx dydx=sec2x⇒slope=4=C y2=10x dydx=102y=5y⇒slope=12=D ascending is A, D, B, C

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