First slide
Theory of equations
Question

If α and β be the roots of x2+px+q=0 then, ωα+ω2βω2α+ωβα2β+β2α isequal to 

Moderate
Solution

Since, α and β are the roots of the equation x2+px+q=0, thereforeα+β=p and αβ=q, Now, ωα+ω2βω2α+ωβ

=α2+β2+ω4+ω2αβ    ω3=1=α2+β2αβ    ω+ω2=1=(α+β)23αβ=p23q    

Also, α2β+β2α=α3+β3αβ=(α+β)33αβ(α+β)αβ=p3qp2q

 The given expression =p23qp3qp2q=qp

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