If α and β be the roots of x2+px+q=0 then, ωα+ω2βω2α+ωβα2β+β2α isequal to
−qp
αβ
−pq
ω
Since, α and β are the roots of the equation x2+px+q=0, thereforeα+β=−p and αβ=q, Now, ωα+ω2βω2α+ωβ
=α2+β2+ω4+ω2αβ ∵ω3=1=α2+β2−αβ ∵ω+ω2=−1=(α+β)2−3αβ=p2−3q
Also, α2β+β2α=α3+β3αβ=(α+β)3−3αβ(α+β)αβ=p3q−p2q
∴ The given expression =p2−3qp3q−p2q=−qp