First slide
Theory of equations
Question

If α,β be the roots of x2+px+q=0 and α+h,β+h are the roots of x2+rx+s=0, then

Moderate
Solution

α+β=-p, αβ=q

α+β+2h=-r, (α+h)(β+h)=s

-p+2h=-rh=p-r2   ...(i)

Now, αβ+h(α+β)+h2=s

q+h(-p)+h2=s

q+(p-r2)(-p)+p-r22=s

q-(p2-pr)2+p2+r2-2pr4=s

4q-2p2+2pr+p2+r2-2pr=4s

4q-p2+r2-4s=0r2-4s=p2-4q.

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