If α and β be two roots of the equation x2−64x+256=0. Then, value of α3β51/8+β3α51/8 is

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answer is A.

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Detailed Solution

Given quadratic equation x2−64x+256=0 having roots α andβ, soα+β=64 and αβ=256Now, α3β51/8+β3α51/8=α+β(αβ)5/8=64(256)5/8=6425=6432=2

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