If α and β be two roots of the equation x2−64x+256=0. Then,  value of α3β51/8+β3α51/8 is

Given quadratic equation x2−64x+256=0 having roots α andβ, soα+β=64 and αβ=256Now, α3β51/8+β3α51/8=α+β(αβ)5/8=64(256)5/8=6425=6432=2