Q.

If α and β be two roots of the equation x2-64x+256=0 . Then the value of α3β518+β3α518 is:

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a

3

b

2

c

4

d

1

answer is B.

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Detailed Solution

α,β are roots of x2-64x+256=0⇒α+β=64 and αβ=256=28α3β518+β3α518=α+β(αβ)58=642858=6432=2
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If α and β be two roots of the equation x2-64x+256=0 . Then the value of α3β518+β3α518 is: