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If for a Binomial distribution  the mean is  10 and the standard deviation is 5  then  P (x = r) =

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a
Cr   20(12)20
b
Cr   9(13)r(23)9–r
c
Cr   12(23)r(13)12–r
d
12Cr(13)r(23)9–r

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detailed solution

Correct option is A

p(X=r)=Cr   n.qn−r.pr μ=np=10σ2=npq=5


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