If, in the binomial expansion of (a−b)n,n≥5 he sum of 5th and 6th term is zero, then value of ab is
n−56
6n−4
n−45
5n−4
nC4an−4(−b)4+nC5an−5(−b)5=0⇒nC4an−4b4=nC5an−5b5⇒an−4b4an−5b5= nC5 nC4⇒ab=n−45