If both the roots of k(6x2+3)+rx+2x2-1=0 and 6k(2x2+1)+px+4x2-2=0 are common, then 2r-p is equal to
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a
-1
b
0
c
1
d
2
answer is B.
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Detailed Solution
Given equation can be written as(6k+2)x2+rx+3k-1=0 ...(i)and 2(6k+2)x2+px+2(3k-1)=0 ...(ii)Condition for common roots is12k+46k+2=pr=6k-23k-1=2 or 2r-p=0