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If $C_{0}, C_{1}, C_{2}, \dots, C_{n}$ are the coefficients of the expansion of (1 + x) ⁿ , then the value of $\sum_{0}^{n} \frac{C_{k}}{k + 1}$ is

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2n−1n

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Correct option is C

Here, tr+1= nCrr+1=1r+1⋅nCr =1n+1⋅n+1Cr+1Putting r = 0, 1, 2, ... n and adding, we get ∑0nCkk+1 =1n+1(n+1C1+n+1C2+n+1C3+…+n+1Cn+1) =1n+1(2n+1−n+1C0)=2n+1−1n+1

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If C0,C1,C2,…,Cn are the coefficients of the expansion of (1 + x) n , then the value of ∑0nCkk+1 is

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If $C_{0}, C_{1}, C_{2}, \dots, C_{n}$ are the coefficients of the expansion of (1 + x) ⁿ , then the value of $\sum_{0}^{n} \frac{C_{k}}{k + 1}$ is