If C0,C1,C2,…..Cn denote the coefficients of the binomial expansion (1+x)n , then the value of C1+3C3+5C5+…+ is
1+xn=C0+C1x+C2x2+C3x3+....+CnxnDifferentiate both sides n1+xn−1=C1+2C2x+3C3x2+...+nCnxn−1put x=1n2n−1=C1+2C2+3C3+...+nCnput x=−10=C1−2C2+3C3+....+−1n−1nCnAdding the above two equations2C1+3C3+5C5+...=n2n−1C1+3C3+5C5+...=n2n−2