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If $a = c i s α, b = c i s β, c = c i s γ$ and $\frac{a}{b} + \frac{b}{c} + \frac{c}{a} - 1 = 0$ then $\cos (α - β) + \cos (β - γ) + \cos (γ - α) =$

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Correct option is B

ab=cisα-β similarly bc=cisβ-γ and ca=cisγ-αnow compare real part

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If a=cisα,b=cis β,c=cisγ and ab+bc+ca−1=0 then cos(α−β)+cos(β−γ)+cos(γ−α)=

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Ready to Test Your Skills?

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If $a = c i s α, b = c i s β, c = c i s γ$ and $\frac{a}{b} + \frac{b}{c} + \frac{c}{a} - 1 = 0$ then $\cos (α - β) + \cos (β - γ) + \cos (γ - α) =$